4^x+1+2^2X-2=158

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Solution for 4^x+1+2^2X-2=158 equation: 



4^x+1+2^2x-2=158

We move all terms to the left:

4^x+1+2^2x-2-(158)=0

We add all the numbers together, and all the variables

4^x+2^2x-159=0

We move all terms containing x to the left, all other terms to the right

4^x+2^2x=159

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